ompf2.com

My concern here is that the results from the path tracer and the results from the light tracer disagree.

Hi, I have implemented a light tracer and a path tracer. For every scene I have tried with a finite-aperture camera containing no lens (i.e., the aperture is just a hole) and a single light, the results match exactly. However, if a thin lens is added, the results differ. Specifically: --If the senso...

I think I understand it now. It's literally exactly the same integral , just with the role of emitter and collector switched. Just as there is no extra cosine weighting needed when an eye-traced ray accumulates radiance from a light, there is no extra cosine weighting needed when a light-traced ray ...

It's a very simple scene:

I have the following simple example: --Sensor: 1 square meter panel, records radiant flux ϕ --Light: 1 square meter panel, Lambertian (constant radiance) emission of L=1.0. --The sensor and light are directly adjacent to each other. You can think of this a sensor plate and a light plate stuck togeth...

Hi, This post intends to be a summary of all the issues I am currently working on. Any input anyone can provide would be welcome. I am currently restricting to area light sources and finite-aperture lenses. The camera model I am using is a circular thin lens with an image plane behind it. The image ...

Hi, I have implemented a light tracer: random light paths are generated, and bounce around until they hit the camera lens, at which point they refract deterministically onto the image plane. I do not know how to weight these paths properly. I understand that one should divide by the number of light ...

I believe I have figured it out myself. To figure out the total power hitting a point on the image sensor, you need to figure out the integral of the radiance hitting it. For Monte Carlo, this is just your radiance estimate (one ray from image sensor to light) divided by the pdf (for evenly sampled ...

I . . . understand that. You can send as many photons as you like. That's not the issue though. The issue is that aperture size and shutter speed affect brightness. This is true for virtual cameras too. It has nothing to do with how many paths you trace or how many exist. Here's a decent image: http...

Why would the exposure time be infinite because the camera is a pinhole ? Think about it this way: the larger the aperture, the more paths there are more light to hit the sensor. For a true pinhole camera, there is only one light path that hits each point on the sensor. This is why real "pinho...